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A bullet of mass 45 g hits a block of mass 3.66 kg with a speed v. After the collision, the bullet emerges at the other end o

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Solution : - mas = m = of bullet 45x10 45g 3M = 3.60 Ry mas of bloch initial velocity of bulket = v final velocity of that -2. 1,2 = 7.6 X10% + 1.22 x103 2 U? = 8.82 X 103 V 93.92 m/s to initial velocity of bullet deullet was 93.92 mle

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