Correct answer is: 0.52

Events A and B are independent with p(A) - 0.2 and p(B) - 0.4. Find p(A...
If A and B are events with P(A)=0.4, P(A OR B)=0.52, and P(A AND B)=0.08, find P(B). Provide your answer below:
Let P(A) = 0.4 P(B) = 0.5 P(A|B) = 0.2 (Please show working). If the events a and b are independent, calculate the P(A and B) If the events a and b are not independent, calculate the P(A and B) If the events a and b are mutually exclusive, calculate the P(A or B)
For two events, A and B, P(A) = 0.4 and P(B) = 0.3 (a) If A and B are independent, find ?(? ∩ ?), ?(?|?), ?(? ∪ ?). (b) If A and B are dependent with ?(?|?) = 0.6, find ?(? ∪ ?),?(?|?).
For two events, A and B, P(A) = 0.4 and P(B) = 0.3 (a) If A and B are independent, find ?(? ∩ ?), ?(?|?), ?(? ∪ ?). (b) If A and B are dependent with ?(?|?) = 0.6, find ?(? ∪ ?),?(?|?).
Events A, B, and C in a sample space have P(A)=0.2, P(B)=0.4, P(C)=0.5, P(~B ∪ ~C)=0.9, and P(A ∪ C)=0.6. Find P(A ∪ B ∪ C) if A and B are mutually exclusive.
let A and B be any 2 events with p(A)=0.2; P(AUB)=0.35; P(A
and B)= 0.15 find P(A|B)
QUESTION 25 Let A and B be any 2 events with p(A) 0.2; P(AUB) 0.35; P(A and B) 0.15 a.0.25 Find P(A|B) b.0.5 c.0.6 d.0.4
A and B are two events such that P(A) = 0.4, P(B) = 0.5, and P(A|B) = 0.3. Find P(A and B). Select one: a. 0.6 b. 0.15 c. 0.12 d. 0.2
9. If P(A) = 0.2, P(B) = 0.2, and P(A U B) = 0.4, then P(An B) = (a) Are events A and B independent? (enter YES or NO) (b) Are A and B mutually exclusive? (enter YES or NO)
8. (1 point) Consider an experiment with events A and B, for which P(A)=0.2, and P(B)=0.4. A and B are independent. What is P(A V B)?
For two events A and B, P(A)=0.4 and P(B)=0.3 (a) If A and B are independent, then P(A|B)= P(A∪B)= P(A∩B)= (b) If A and B are dependent and P(A|B)=0.6, then P(A∩B)= P(B|A) = 2. All that is left in a packet of candy are 8 reds, 2 greens, and 3 blues. (a)What is the probability that a random drawing yields a green followed by a blue assuming that the first candy drawn is put back into the packet?