Question

19 mass Position, Velocity Ball 12.00 1.00 1.00 Balla 11.50 12.00, 1o.ool v.-v2=va vi m Nitmaua = m, uimara mas position Verdcity Ball I 0,50 1.00 1.00 Ball al3.00/2.00/0.00 mivirmavaamis+maval has 3 position Netecty Ball 10.50 1.00 12.00 Ball 2/1.50/2.00 10.00 vi-va-varri miritmava-mutmawal 2-ova-vi (0.5) (2+0 = 0.5vI+ (1.5)(aru) a triva 0.50 +3+lisri Va = 2+(-1) -2 = ari va = I mise - 1 m/sec = ut Ainin Velocity Menucececente Ball 10.50 1.00 Ballati.so 2.00 Beeld -1.00 Wi-va-va-vi m, ritmava =mirtmavo mass Loo A.

The information with the balls and help plug it in to solve the equation.

Answer 1

Given two ball mass (kg) Position (m) [Velocity - Ball 2 1 two equation given V - 12 = 11 - V mu, + MgV₂ = mvi + Me Val Petting value in cho 1-o.co=V-vil V. - Vi Putting value in eno 2 con +1.504, 2 X1 + 1.Toxo = 2 9+2 21, + 1.50V) ogn 9 x 2 at can 216 +1.501 3.541 - 4 = 1.14 mis Putting in o so V = 14 ml and a Polly mis

mass Position Velouty Ball-1 Ball-2 3.co Griven een V, V₂ = 11. Vil emiu, ofm, ₂ = Muitma ve Putting valuer can 3 0.5 Va! -V,' = 1 Putting value in een a (6.50) (10m) + 8.00 210.00) = 0.501' 43. cola! 0.50v,' t 3. cola - Solving can and ♡ can multiply 0.5 t can 9 0.5V + 3 colha! V = 0.28 ml Duetting in con ♡ V = 0.28-1 Vi = -0.72 ml . So, Vi= -0.12 mis , V = 0.28 mb -0.5 tor 3.50 V -0.92

نما mass Position Velouty Bell- 1.50 Ball-2 Given con V, V = Val-V, ' - Q Muit Ma V₂ Matmu - Putting in value can 2.000 V = 2.otvil Putting value in can (0.5)(2000) to 0.5011 tl. sove 1.50V2' + osovil 1 = 0.50V,' + 3 + 1,5 vi! 2.0 V, y = - 1 ml Putting in een My = 2.00: = 1 m/s Lo Vilalmis and a = 1 ml Ite Cc

0.50 -1.00 mass Porition Velocity Ball-1 Ball-q 1.50 given cqn V-V = Val-Vil Movit Male = movi + Mg Val Peetting value in can - (-1) = 1 1 1 Iti = 1/-vl V = 2t4 - ③ Putting value in ean E (65) (1.00) +11.50) (100) = -54%! + 1.501 =.54,1+1.50v =1.502 +0.541 1.501 2+ v,!) to.5V 3.0 +1.5 V,' to.IV, 2.ou! V = 2 m/s -4.0 So Vi= ~2 m/s and val