Question

Problem 6 30° W F M B •E A C d L L L = 2 m d = 1.6 m F = 4.3 kN w = 3.2 kN/m M = 6.9 kN.m Determine the internal normal force, shear force and bending moment at point E, located in the middle of BC.

please show all work clearly

Answer 1

3.2x16= 5.12KN feasso -6.9 kN.m M poco E flinzo HA for k 1.6m RA RB KGK 키 K * L=2m L=2m L=2m frosso = 4.3 cos30=3.724 f sinzo24.3 sinzoz 2.15 kn E fx=0 HA= f binzo 2.15 Kw => HA=2.15 kn E fyzo RA TRB = 5-12 + f2053 RATRB=8.844 KN EMASO Feos30x6 +5.12 (6-008) – Roxy -6.9 = 0 Ro= 10.517 KN = > RAF - 1.673 kW

Now (i) Normal force co e a HA = 2-15 kn cii) Shear Jorie at E '= RATRB-3.2 [0.6] (1 -1.673 +10.512 -1.92 - 6.919 kn - fcos 30 XI - 3.2 x 1x.s •B.M -5.324 knom ciii Bendling Momew at 't'a con calculated from either) Sicle of left or Right from 'E' (Eve) sign repreats hogging'
hey i have calculated shear force and normal force taking section of beam left of point E

and bending moment have calculated using right side beam from point E