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Determine the potential for the field: } = (-6 cos (2y), 12x sin (2y), 5 cos (1z) – 5z sin (1z)) Do not put the constant +c

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Apart F - <- 6 cos (24), 12x sin (24), 5 cos2 -52 sin2) (OD + hesaxe . fe S-6 cos lay) de by = fizesinzy day = -12x coin2y +ar = 7 4) = afsind] + 4 cost + 3 2-4 sind î + 4 cost ŷ + 3 % rict) J16 sinal + 16 cost + 9 S 16+9 125 = 5 こ --Resitjag et3644

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