Question

9. As shown in Figure 5.30, the jet flow of water with flow rate Q and diameter d is angle θ.

Is hitting the stationary plate of. Find the force and the direction required to support this stationary plate. Also, find Q1, Q2, and F when θ = 60°, d = 25 mm, and Q = 0.12 m3/s.

9. 4 ahald Q2

Answer 1

F= mass striking plate per writ time Redention in velocity in the direction (Pav) (usino) = parasino E - o= 60° Q= 0.18 m d = 25mm given solo asarea of jet = 74d" - 44(25x162) a= 4.90848104 2 8 = av v=/a= 0.12 4.9087x154 lu= 244.462 mis P = 1000 kalon water. F = Pav² sino = 1000x4-908 x 54 x (244.4 x singo F = 25.40 KN

Applysing impulse momenten cueitin in tangential direction (Par-lQ2v) - CQ v cose=0 (9.-Q2) - Qlose- since no friction belo betwen later & plate Vi=V2=v. encation now continuity 8=Q,+Q2. - 2 Sawing evlation 0.12 Ci+cos so) - 0.09 m/s Que (1760) Q2 = 9 (1.- Loso) 0.12 C1-costo) = 0.03 m/s 2 9,-0.09 ms Q2 = 0.03 m/s 7,8 IV = V2 = V Since there is no friction between water & Plate (Assumed)
if any douts are there please to comment , thank you