Question

Problem 2 [15 points] In a two-slit interference experiment, the slits are 0.1 mm apart and the screen is 1 m from the slits. The m = 1 bright fringe is 10 mm apart from the central bright fringe. a) [10 points) Calculate the wavelength of the light b) (5 points) Calculate the distance from the central bright fringe to the m = 3 bright fringe. General Physics 11 PHYS 219 2 Page Problem 3 (15points) Consider a concave spherical mirror that has focal length f = +18.0 cm. a) (5 points) What is the radius of curvature of the mirror? b) (10 points) What is the distance of an object from the mirror if the image is real and has the same height as the object?

Answer 1

2) d = 0.1 mm - 0.1810 m D= Im (9) Given bandwidth, B = 10 mm= 10x 103 m 10x10²x0.1x103 d B = do - Bd 1600.nm) - 30x10 m (6) distance 3B = 3x10 mm = 30mm 3 R = 2f = 2x 18 = 36 cm (b) when an object is placed of the center of curvature, we get the image of same height. Hernce required distance, R = 36 cm