1. Use the data given to calculate the value of
ΔG°rxn for the reaction at 25 °C.
2 C(graphite) + H2(g) <--->
C2H2(g)
|
C(graphite) |
H2(g) |
C2H2(g) |
|
|
S° (J/mol ⋅ K) |
5.74 |
130.68 |
201.0 |
|
(kJ/mol) |
0 |
0 |
−226.8 |
Report answer to four significant figures.
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1. Use the data given to calculate the value of ΔG°rxn for the reaction at 25...
Please answer with correct sig figs
Use the data given to calculate the value of AGºrxn for the reaction at 25 °C. 2 C(graphite) + H2(g) C2H2(g) C(graphite) H2(g) C2H2(g) Sº (J/mol · K) 5.74 130.68 201.0 (kJ/mol) 0 0 -226.8 Report answer to four significant figures.
does anyone know how to solve this ?
i
put both -207.6 and also 322.3 as the answer but it was marked
wrong both times.
QUESTION 1 Use the data given to calculate the value of AGºrxn for the reaction at 25 °C. 2 C(graphite) + H2(g) C2H2(g) C(graphite) H2(g) C2H2(g) 5.74 130.68 201.0 S" (J/mol · K) (kJ/mol) 0 0 -226.8 Report answer to four significant figures.
Use the following data to calculate the value of ΔG°rxn at 298 K for the reaction described by the given chemical equation. Include the units. Compound S°f (J/molK) DH°f (kJ/mol) CO (g) 197.7 –110.5 H2 (g) 130.7 0 CH4 (g) 186.3 –74.6 H2O (g) 188.8 –241.8 CO (g) + 3H2 (g) → CH4 (g) + H2O (g) I got -141.9 KJ/mol, but i think the units are wrong and I don't know why.
(a) Use the data given below and calculate ∆Ho, ∆So, ∆Go, and Kp at 25° C for the reaction: C2H2 (g) + 2 H2 (g) → C2H6 (g) (b) Calculate ∆G for the reaction at 250 °C. (c) At what temperature (°C) is ∆G equal to zero? In what temperature range is this reaction productfavored? Compound ∆ Ho , kJ/mol S o , J/mol• K C2H2 (g) 226.73 200.94 H2 (g) 0 130.68 C2H6 (g) -84.68 229.6
(a) Use the data given below and calculate ∆Ho, ∆So, ∆Go, and Kp at 25° C for the reaction: C2H2 (g) + 2 H2 (g) → C2H6 (g) (b) Calculate ∆G for the reaction at 250 °C. (c) At what temperature (°C) is ∆G equal to zero? In what temperature range is this reaction productfavored? Compound ∆ Ho , kJ/mol S o , J/mol• K C2H2 (g) 226.73 200.94 H2 (g) 0 130.68 C2H6 (g) -84.68 229.6
For each of the following reactions, calculate ΔH∘rxn, ΔS∘rxn, and ΔG∘rxn at 25 ∘C. State whether or not the reaction is spontaneous. If the reaction is not spontaneous, would a change in temperature make it spontaneous? If so, should the temperature be raised or lowered from 25 ∘C? N2(g)+O2(g)→2NO(g) Express your answer using three significant figures. ΔH∘rxn ΔHrxn∘ = 183 kJ SubmitPrevious Answers Correct Part H Part complete Calculate ΔS∘rxn at 25 ∘C. Express your answer to one decimal place....
Calculate the entropy change at 25°C for the following reaction: 6 C (s,graphite) + 3 H2 (g) → C6H6 (l). The entropy contents of the reactants and product at 25°C are as follows: Substance S, J/mol•K C (s,graphite) 5.74 H2 (g) 130.68 C6H6 (l) 172.8
Use the given data at 700 K to calculate ΔG°for the reaction H2(g) + CO2(g) → H2O(g) + CO(g) Substance H2(g) CO2(g) H2O(g) CO(g) ΔH°f(kJ/mol) 0 -393 -242 -111 S°(J/K·mol) 131 214 189 198 -472 kJ 10.6 kJ -775 kJ -2.94 x 104 kJ
Calculate ΔG° at 298.0 K for this reaction given that ΔH°rxn = –12.0 kJ and ΔS°rxn = –147 J/K
Given the following hypothetical reactions and ΔG°rxn's, calculate the ΔG°rxn in kilojoules per mole for the final reaction. A(g) + 12X2(g) → AX(g) ΔG°rxn = -119.2 kJ/mol ZX4(g) → Z(g) + 2X2(g) ΔG°rxn = 427.6 kJ/mol JX3(g) + 3AX(g) → JA3(g) + 3X2(g) ΔG°rxn = -472.2 kJ/mol Z(g) + 4AX(g) → ZX4(g) + 4A(g) ΔG°rxn = ??? kJ/mol