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Consider one span of a continuous beam has a concentrated load P=120kN applied at mid-span. The span of the beam L=6m. P L/2

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오 02 M2 = 540 knom A 6 m B 9. + TEMA 30 540 = V8x6 VS- 9ok Sfuso T + VA = SOKN ܥ 9. R A = - 90KN Ans 10. RINB go KN Ans K 3mErya -1573 + 6x +(2 Boundary Condition x=0, y=0 C 220 x=6m, y=0 4 5)/54 540 KN-m2 :. El ef aug ef aug olm 2-3 m => -15*33 + 5

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