HomeworkLib
Question

Will a ppt of SrF2 (s) form if you mix 7.7 x 10-4 M Sr(NO3)2 (aq) with 3.8 x 10-5 M NaF (aq)? (Which of the following is enti
science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

and SYCNO3)2 completely NaF both are gonic salt and give constituents ions. dissociare Sr CNO3) 2 sr2+ 2 No3 Esyty z [sr (NO3

0 0
Add a comment
Know the answer?
Add Answer to:
Will a ppt of SrF2 (s) form if you mix 7.7 x 10-4 M Sr(NO3)2 (aq)...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • Suppose a solution is made containing 7.3 x 10-3 M Sr(NO3)2(aq) and 8.3 x 102 M...

    Suppose a solution is made containing 7.3 x 10-3 M Sr(NO3)2(aq) and 8.3 x 102 M NaF (aq). Calculate Q and determine whether a precipitate of SrF2 (s) will form. (In other words, which of the following is entirely correct?) Ksp of SrF2 = 2.8 x 10-9 a. Q = 5.0 x 105, ppt forms b. Q = 5.0 x 10-5, no ppt c. Q = 2.0 x 104 ppt forms d. Q = 6.1 x 104.ppt forms e. Q...

  • solution 15 made containing 7.8 x 10-3 (Sr(NO3)2) 25.) suppose and 8.3 x10-2 NaF (aq). Calculate...

    solution 15 made containing 7.8 x 10-3 (Sr(NO3)2) 25.) suppose and 8.3 x10-2 NaF (aq). Calculate Q and determine wheter a precipate lydstupem of SrFe will form. Ksp of SrF2= 2.8x10-9 ppt forms forms no ppt CQ = 2.0 110-4 pot forms ppt no ppt e Q= 6.1810-4 a. Q = 5.0 x10-5 b Q = 5.0 X1D-5 d Q = 6.1 810-4

  • 200 mL of 0.0010 M Sr(NO3)2 (aq) are mixed with 800 mL of 0.0050M NaF (aq)...

    200 mL of 0.0010 M Sr(NO3)2 (aq) are mixed with 800 mL of 0.0050M NaF (aq) to make 1.0 L of solution. The Ksp value of SrF2 is 4.3 x 10-9. Which is correct? I know the answer, I just don't know how they got to it. a. SrF2 will not precipitate. b. SrF2 will precipitate. NaF is the limiting reactant. c. SrF2 will precipitate. NaNO3 is the limiting reactant. d. SrF2 will precipitate. Sr(NO3)2 is the limiting reactant. e....

  • Suppose 50mL of 8.4x10-7 M Pb(NO3)2 (aq) is mixed with 200mL of 9.7x10-4 M Na2CO3(aq). Calculate...

    Suppose 50mL of 8.4x10-7 M Pb(NO3)2 (aq) is mixed with 200mL of 9.7x10-4 M Na2CO3(aq). Calculate Q and determine whether a ppt of PbCO3(s) will form. (In other words which of the following is entirely correct?) (Suggestion: Write the dissolving equation and Ksp expression for PbCO3 before starting this problem). a. Q=8.1x10-10 , no ppt b. Q=8.1x10-10 , ppt forms c. Q=1.3x10-10 , no ppt d. Q=1.3x10-10 , ppt forms e. Q=2.5x10-9 , ppt forms

  • ore for this quiz: 67 out of 100 bmitted Jul 21 at 11:47am is attempt took...

    ore for this quiz: 67 out of 100 bmitted Jul 21 at 11:47am is attempt took 160 minutes. 0/3 pts correct Question 1 Will a ppt of MgF2 (s) form if you mix 65 mL of .60 M Mg2+ (aq) with 235 mL of 7.0 x 10-7MF (aq). (Which of the following is entirely correct?) Q = 3.9 x 10-14, no ppt Q = 4.0 x 10-13, no ppt Q = 2.9 x 10-13, no ppt Q = 4.2 x...

  • 12 – A solution of 0.060 M NaF (75 mL) is mixed with 0.15 M Sr(NO3)2...

    12 – A solution of 0.060 M NaF (75 mL) is mixed with 0.15 M Sr(NO3)2 (25 mL). Calculate the concentrations of each ion after equilibrium is achieved given Ksp for SrF2 = 2.0 x 10-10.Hint: The ion exchange reaction to produce SrF2 can be considered to go to completion before equilibrium is reestablished starting from the products, much as we’ve done for titration calculations at the equivalence point 13 – a) Calculate the molar solubility of hydroxyapatite given Ksp...

  • Question 7 Determine the solubility of Cul(s) (Ksp = 1.1 x 10-12) in 0.15 M Cu(NO3)2(aq)...

    Question 7 Determine the solubility of Cul(s) (Ksp = 1.1 x 10-12) in 0.15 M Cu(NO3)2(aq) solution 1- 1- Ksp = (S+ 0.15). (25)?. S = (Ksp/0.6) 1/2, S = 1.35 x 10-6 M 2- 2- Ksp = S . (S + 0.30). S = (Ksp/0.30), S = 3.67 x 10-12 M 3- 3- Ksp = (S + 0.15).S. S = (Ksp/0.15). S = 7.33 x 10-12 M

  • Will a precipitate form when 35.0 mL of 0.25 M Mg(NO3)2 and 65 mL of 0.15...

    Will a precipitate form when 35.0 mL of 0.25 M Mg(NO3)2 and 65 mL of 0.15 M NaF are mixed together? Ksp for MgF2 = 7.4 x 10". Your work must justify your answer. MgF2 (s) + Mg2+ (aq) + 2 F (aq) Calculate the Ksp for vanadium hydroxide if the solubility of V(OH), in pure water is 1.1 x 10-7 g/L. V(OH)35 V3+ + 3 OH Label each of the following salts as acidic (A), basic (B) or neutral...

  • You prepare a solution by mixing 400.0 mL of 1 x 10-4 M Mg(NO3)2 and 500.0...

    You prepare a solution by mixing 400.0 mL of 1 x 10-4 M Mg(NO3)2 and 500.0 mL of 1.00 x 10-4 M NaF. What is the observed outcome? For MgF2, Ksp = 6.4 x 10-9. A. A precipitate forms because Qsp > Ksp. B. No precipitate forms because Qsp > Ksp. C. No precipitate forms because Qsp = Ksp. D. No precipitate forms because Qsp < Ksp. E. A precipitate forms because Qsp < Ksp.

  • For the reaction Ba(OH)2 (s) -- Ba2+ (aq) + 2 OH (aq) a precipitate will form...

    For the reaction Ba(OH)2 (s) -- Ba2+ (aq) + 2 OH (aq) a precipitate will form if Q< K. Select one: True False Into a solution of 0.10 M KBr and 0.10 M KCYOA you add 0.050 M silver nitrate dropwise until a precipitate forms. Ksp for Ag2Cronis 9.0 x 10-12. Ksp for AgBr is 5.0 x 10-13. Which of the following will precipitate first? Select one or more: a. silver chromate b. no precipitate will form C. silver bromide...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT