Question

E CALCULATE THE MOMENT of INERTIA OF Ring throught the center o mas) (the axis goes to 2 ) your ege?) inerlia of calculate the moment of a ring thorought to the throught P; Find Ip • Ip axis parale passing previous axis axis and I am . Р

Answer 1

le AS Inertia koow moment of given by - fams? - - element de O (where dm il mars your lipithe distance from the its of potatom, Wowmass of the doll small element dt=Roda dm = tal NR.de .M maus QTIR per unit length of the ri ring Now moments of inertia about the axis of rotation pasting through the centre of mass perpendicular to the plane where w density and

of the sing. Iz = Icm P2 where m र ज्वाण न काल गण, trto R2 Jc M TIR Rda R 12 ल b श toigoel ( ०- शा nat RI Then Icm 0 fel de PATTETAP (शा) tage M 7 Iom ४ 2 * How w to now from the perpendicular axis therem Ise tly Izi there वाए वह passing through the centre and in the ring plane on fanis goes to edged 1x माब श

mome edry of ring Due to sy fy I- In IZ avertin II I ģ Iz 3 Mp? , 6 R 1 parallel anis theorem Now from Moments of inertia, about ein axis parallel to another etnis is given by Icm + M Where Icom is moment of inertioi about an axism which is parallel to our concerning axis Ip 2тпе? +Р4p2 I'p 3 . (Im = MR? we already deducedy