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The beam ABC is supported at A with a guided support (fixed with roller) and hinge at B has rectangular cross section and sup

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Answer #1

support reaction - solution an - d at0000 a Deura giren AB b ke 112 12 L12 > maximum tensile frimciple sk Strees at point D == temsile normal strus at point D > 6m = mxy 1.9P x 87 bha 12 » 6n = 1.9 p/krv) X IWON x 87 Jun 50x2503 where pis in un - 60TD Simeop Со = ) = 61.88X100mpa 8 = Sim20p (onito TED Marionum principle Strees = 60 + 8 e E dor! H 3 -) 63 61.88X10-3 P + 2.

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Answer #3

D = 37 mpa Given That Principal stress at Length Of Beams (-) = 1.99 Breadth of Beam (1) - 50 mm Height (H) = 2500 and also Gcalculate Centroid in the beam els bod 87mon aso -38 2 Y-87 corso calculate shear stress syco) wa shean folce Qa first momentwe know that, 3 Stress comenty 7xd-- -(-PL)xy 고 + CPxLx27 x16 mm2 6.518107 mmuz yom 2539.140 W/m2 Two gol que Ox= 2539217p Noa=2539.17P t J62539/1973+ (61.844p2 ☺ 2 By solving 2.547103 p. 2540.67 P aa substitue 2589087 37 mpa oi, stress Q (0) - Nom²

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Answer #2

Р EV =0 7 P-PARE SO <%=0 - ( 1 8 A Ro=0 + 0.95m 6.95m 1 0.95m 3 SO 50X dio 38 Shear fence at D, V=P Bending moment at D, MUp Vote the Solution. Thank you ?.... Stay Safe

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