Question

please answer asap

Problem 2 In the given RC circuit, a capacitor is connected to a resistor in series and is getting charged after closing the Switch. The time constant of the circuit is 10 (S). R = 109 (12) C =? (F) O A- Calculate the capacitance of the capacitor. B- How much time does it take for the capacitor to become fully (about 99%) charged? C- If we close the Switch and the capacitor starts getting charged, what is the charge at the 5th second of Switch being closed? D- How much time does it take after closing the Switch for the current in the circuit become 0.5X10-8 (A)? E- What is voltage across the capacitor at the 5th second of Switch being closed? F- What is the energy stored in capacitor at the 5th second of Switch being closed? Switch V = 10 (V)

Answer 1

So t c) charge att=ss We know Time Constant = RC = 10 A) 10 = 108f = lonf so = R 109 capacitance (c= ionf 1) are know Chargeon Capacitor q=&m (1 - 0 1 - 2 ) Here q = 0.99 am -t/e so étle_oool so 0.99-1-e + = 4.605 solt = 46.055 (Qmax-cy 9= CV(1-e *'() = 16810[1-6-95 9=6.065810-80/= D) Current incircuit - the Im = 10-8A i=o.5X108 A so i = é the 0.5 = e the Im o the = 0.693, t = 6.935 E) Voltage acron resitor VR-IR Vp = 0.5X108 109 = 5v [vc= 10-VR=sy) IF U = 1 cy² = 1x108x25 U= 12.5X108 10=125nJ oss 60.65nC i= Ime 2