Question

-refer to a vertical cylindrical beaker holding water. The density of water is 1.0 g/cm³. The volume of a cylinder is πR²H, where R is the radius of the cylinder and H is the height.

If the beaker holds 1.49 kg of water and the bottom of the container has a diameter of 7.35 cm, what is the water pressure at the bottom of the cylinder in Pascals (N/m²)?

Answer 1

p=bag Answer o The pressuce at (9-81 mls) 9 post in flends can be calculate do h: Height / depts of licit s : dessits of liquial Gavitational pull Ch) Cinen mass = 1-49 leg densito 21.9603 & - tovo kg/m H 11 R=7.35cm

1.49 Volume = mass -2 loo densito R 27-35*10 m 2 T RH 1.49 1.49 1000X A XR² 1000 0.0877933 m 1.49 H = low rax G 35x10 22 Cuctes pocose at battery, P=159 = 0:0S 19933 X 1060* 9.81 = 861.25 M2