Calculate ΔHo for C6H6 (l) + 15/2 O2 (g) → 6 CO2 (g) + 3 H2O...

Question

Question

Calculate ΔHo for C6H6 (l) + 15/2 O2 (g) → 6 CO2 (g) + 3 H2O (l)

from

ΔHof C6H6 (l) = 49.0 kJ

ΔHof CO2 (g) = - 393.5 kJ

ΔHof H2O (l) = -285.8 k J

science chemistry

Answer 1

Answer #1

СсHg (1) + 15 о, () --> 6c0, (а) + 3H,0 (1) AH= Enf 4 Hoof product - En; 4 Ho,f, nenetant Gх дн. ДНco, + 2x AHн,о 1x AH cette

Answer 2

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