Question

1. ( 4 points) Two planes take off at the same time from an airport. The first plane is flying at 300 miles per hour on a course of 135º. The second plane is flying in the direction of 175° at 400 miles per hour. Assuming there are no wind currents blowing, how far apart are they after 3 hours? 2. ( 4 points) Vector V is in standard position and makes an angle of 60° with the positive x-axis. Its magnitude is 9. Write Vin component form (a, b) and in vector component form ai + bj. 3.( 4 points) Multiply. Leave all answers in trigonometric form. 9 cis 20°. 4 cis 195

Answer 1

N soll In the figure, First plane at A 900 miles after 3 hours. second peone at B after 3 hown 135 175 1200 miles B →E distance covered by first plane en 3 hu = 300 X 3 = 900 miles ОА est in z his distance covered 400 x 3 = by second plane 1200 miles OB Also, LAOB = 1750 – 135º = 40°

للنههعسقط منها . b +2م - 20h cosc AB= oA' + OB? - 200A) COB) Los (LAB) (مد) ه (وند) همود - زومعلم+ رووف)=Ad دولا همدم دوم مقلد - وم موكله ومهمله = 595344 : اگه وگون - هه مه کرد هم رو 5853 ولت - AB 595344 AB = 11.59 Then, the planes are 771.59 miles for apart. The component foom يش فهد العللروه الول > = ( طره > and vector component form in ait bj - قصد الحال+ شقه للكل Given Magnitude Hy]) = 9 ( angle with tre x-anis) وه = 8 then, y = < 9.combo, a sin 60° z < ( تلفو(4) و تبه دو

3 Multiply 4 cis 1930 a cis 20% Weing formula for multiplicatum ef two complex numbers let 2 d, cisa, په کنځور در 2.2= didh cisco, to we get q cis (200). 4. cis (1959) 9.X(4) cis (20° +1959) 36. cis (215°). 9 cis (20°). 4. cis(195) = 36 cis (215)