
8) Find the points (x,y) on the curve given by x = 1+t2 and y=t-t3 where the tangent line is horizontal. Graph the curve and locate these points. Provide scales on both axes. Suggestion: On Desmos, let-2 st s 2 to see the full curve and to estimate where these points are. Points
8) Find the points (x,y) on the curve C given by x = 1+ t2 and y = t – t3 where the tangent line is horizontal. Graph the curve and locate these points. Provide scales on both axes. Suggestion: On Desmos, let -2 st s 2 to see the full curve and to estimate where these points are. Points
Find the points (x,y) on the curve C given by x = 1+t? and y = t- t3 where the tangent line is horizontal. Graph the curve and locate these points. Provide scales on both axes.
-/10 POINTS Find an equation of the tangent line for the curve x=tet, y=t+et at the point corresponding to t=0.
4. Consider the following curve given by the equation x3 – x²y + 4y2 = 8. a. (4pts) Find dy dx b. (3pts) Find the equation of the tangent line to this curve at the point (2,1).
25. Given the following parametric curve X(t) = -1 + 3 cos(t) y(t) = 1 + 2 sin(t) 0<t<21 a) Express the curve with an equation that relates x and y. 7C b) Find the slope of the tangent line to the curve at the point t c) State the pair(s) (x,y) where the curve has a horizontal/vertical tangent line. 27.A particle is traveling along the path such that its position at any time t is given by r(t) =...
The curve Cis given parametrically by x = t2, y = y(t), and intere'. Find the interval of t where curve C concaves upward. o(-00,00) (0,1) (0,0) o(-0,0)
Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter. x = t4 + 3 y = t3 +t t = 1 y(x) = _______
Find the tangent equation to the given curve that passes through the point (4, 3). Note that due to the t2 in the x equation and the 3 in the y equation, the equation in the parameter t has more than one solution. This means that there is a second tangent equation to the given curve that passes through a different point. x = 3t2+1 y = 2t3 + 1 y = (tangent at smaller t) y = (tangent at larger t)
Find an equation for the tangent line to the curve at the given points. y = x2 – 5x + 4 at the intercepts (1,0),(4,0), and (0,4). y = at (1,0) y= at (4,0) y = at (0,4) Sketch the curve and the tangent line. VA VA X 4 Submit Answer