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- Find the area of the surface with parametric equation X=2², yuv, 2 = va and olusa, osusle
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Answer #1


Run) = < u² Ru= osus2 Osus2 < 24, V,0> Rvs <0,4,v> RuXRv ܕܝ -i[uo] -1 (suv-o) + f [ 249) = <v?, -2uv, 24s | RuXRv) = (22) ²+

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