Question

Question 2 If the ratio of base to acid in a buffer increases by a factor of 10, the pH of the buffer: o doesn't change O decreases by 10 increases by 10 increases by 1 O decreases by 1

Answer 1

Ans- pH increases by 1

Explanation-

We know a buffer is a solution were both a weak acid and dits conjugate base are present. Now te pH of a buffer is calculated by the Henderson- Hasselblach equation-

pH = pKa + log [conjugate base] / [acid]

Now the pKa value for a particular acid is always fixed.

Now lets say the ratio of [conjugate base] / [acid] was initially = 1

Thus initial pH = pKa + log [1]

pH = pKa + 0

pH = pKa

Now after increasing by a factor of 10 means now  [conjugate base] / [acid] is = 10 * 1 = 10

So the new pH = pKa + log [10]

pH = pKa + 1

That means the pH increases by 1