Question

Seawater is to be desalinized by reverse osmosis using the scheme indicated in Figure 1. Use the data given in the figure to determine: (a) The rate of waste brine removal (B) (b) The rate of desalinized water (called potable water) production (D) (c) The fraction of the brine leaving the osmosis cell (which acts in essence as a separator) that is recycled (หมายถึง R/F มีค่าเท่ากับเท่าใด) Brine Recycle (R) 5.25% Salt ......% H2O G F = 1000 lb/hr Seawater Reverse Osmosis Cell Brine waste (B) 5.25% Salt 4.0%Salt % H2O 3.1% Salt ......% H20 Desalinized water 500 ppm Salt % Salt ......% H2O

Answer 1

Hey there Dear Respected student,I hope you're doing absolutely great, I'm too glad to answer such a nice question for you. I hope it helps you. I tried my best to provide you with a best quality answer for you . I tried to utilize my full time and knowledge for this question. Its quite easy and simple.. I believe that you will understand this in one read. Yes you can do this my dear . Please carefully go through answer till last word. And oh yes I appreciate your hunger of grabbing knowledge keep it always up like this.

So here is your answer :

The Mecycle System Comprises of process ein which the material is recycled by feeding material from a downstreams_snit to an upstream. A recycle Systers compriſes of one ou make recycle Streams A recyclé Stream_es the stream containing the recycled material. The basic flow diagram_stream can be explained as follows: -Recycle Feed Process 1 - Process 2 -> Products The rate This shows i ☆ stecycle System with one recycle stream @ Refere the figure SAT6.3P3 face the mass fractions & the components of the recycle systems. feed of the recycle_system is 1000 lb/he . The seawaten after severse Osmosis gives desalinated water and bruine solution as producte. The brine Solutions pontially recycled into the system The reate desalination of Water P and the rate $ waste boine removal is B. The balanced equations for the whole Systems are: 2 8+ P = 4000 0.031 x 1000 = 0.0525 x B + 0.005 XP Form equation ① and ② , the value B is : 547.4 lb/he, Hence the rate of waste brine seemoval is 547.41b/ hee B

figure SAT 6:323 e Refere the figure SAT 6.3P3 for the mass fractions of the componente the secycle system. The gate of desalination of water is P and the rate of waste brine removal is Be The balanced equations fove the whole systems are ; Bt • đo0o. 0.03.1% 1000 = 0.0525 X B + 0.005X P..... Foum equation (1) and (2), the value of Pis! P= 455.6_1b/he Hence, the rate % test desalination water is 452.6 lb/hee Refer the for the mass fractions of the components of the recycle system. The waste brine is recycle is the cycle and mixed with the seawater. The rate of brine recycled is R. The rate * salt Water fed into the reverse Osmosis cell is G. The balanced equation you the mixing point as the dystems is: G (3) 0.031 (1000) + 0.0525 (R) = 0.04 (61) ... (4) From equation (3) and (4), the Value of Ris: R = 720 16 thee Now, the total brine removed from the levende osmosis cell is: Tbrine B+R 1267.4 16/he Thus the fraction of brine Mecycled : Fraction of brine cecycled = 720b/hele 12.67.4.1b/h4 1000 + R = = 0.568 Hence, the fraction of brine recycled is 0.568. Thanks

Please Feel free to ask you doubts if any. Your suggestions are most welcomed.
Please appreciate my efforts and hardwork by upvote/thumbs up ? it will be really very helpful .
Thanks for your valuable time.
Thanks for choosing this platform. All the best for your future and career. Keep learning like this always. Stay safe stay healthy. Take a good care of yourself and family . Have a great life ahead

Thanks you so much :)

Answer 2

How 500 ppm is 0.005?