Question

An artist working on a piece of metal in his forging studio plunges the hot metal into oil in order to harden it. The metal piece has a mass of 50 kg and its specific heat is 0.1027 kcal/(kg · °C). He uses 810 kg of oil at 35°C. The specific heat of oil is 0.7167 kcal/(kg · °C). Once the metal is immersed in the oil, the temperature reaches an equilibrium value of 40°C. How hot was the forged metal piece just before he plunged it into the oil?

Answer 1

Answer: heat gain By prociple of Calorimetry [Heat lessed by but body of Cold body before het it be temperature of bet metul piece just Played into the oil, after planging it after planging it into the oil reaches equilibrion Initial temperature al was 35c and it becomes 400 cotter Constant with but metal. knposature with oil of 40°c.. Charge Too- o poi oi) we know Heat lossed or gained during temposature mimass of Substance Cp: Speutic half Het metal Substrie OT : Chase of tenpresature G0-1027 kcaligo OTO 0-7167 Iccal 810 kg man 50 scy allige bitas temp. To 352 Final tepante 40°c 40c & Qcnetul soal 50 X0-1027 G -40) - St6X0.7167 (40-35) 5-135 (T-40) = 290 2.635 =) T-40 = 565.26 & Initial tenperater of T = 605.260 hal metal

Answer: heat gain By prociple of Calorimetry [Heat lessed by but body of Cold body before het it be temperature of bet metul piece just Played into the oil, after planging it after planging it into the oil reaches equilibrion Initial temperature al was 35c and it becomes 400 cotter Constant with but metal. knposature with oil of 40°c.. Charge Too- o poi oi) we know Heat lossed or gained during temposature mimass of Substance Cp: Speutic half Het metal Substrie OT : Chase of tenpresature G0-1027 kcaligo OTO 0-7167 Iccal 810 kg man 50 scy allige bitas temp. To 352 Final tepante 40°c 40c & Qcnetul soal 50 X0-1027 G -40) - St6X0.7167 (40-35) 5-135 (T-40) = 290 2.635 =) T-40 = 565.26 & Initial tenperater of T = 605.260 hal metal