Question

6. Suppose that as S’- frame is rotating with respect with respect to a fixed frame having the same origin. Assume that the angular velocity o of the S’- frame is given by w = 2ti-t?j + (2t+4) k Where t is time and the position vector r of a typical particle at time t as assumed in S’ – frame is given (t+1) i - 6tj +4+3 k.Calculate the Coriolis acceleration at t=1 second. (2013) by1 = 7. Calculate the horizontal component of the Coriolis force acting on a body of mass 0.1 kg moving north ward with a horizontal velocity of 100 ms -1 at 30° N latitude on the earth. (2013)

hand writen answer is accpetable not it should be clearly explained , please explain properly both the question , dont attempt any 1 of them

Answer 1

Answerll 6 s is the spotating frame If is the fixed frame with some ossigin we Consider a particle in s frame which arotake with Wangular velocity. with respect to f frame.us to offrame is, o the velocity of a moring particle relative where, sling= Hence the sh S St + wyz frame st dt detitt Brname Acceleration is given by, JA dit + OXA s frame 'Fixed frame f = 65 toxo St - Str + Swo xñ +Wxl@x) + año y sont where, -200 x 85 is the cossiolis acceleration. & coniolis fonce, Foriotis St 2m Exo Now, we have given, W = at î_dj + (21+4) Ř & 5 = (441)i- 6tj + 4+3 12. then i Bor 1 = 2t ? - 69 + 12th a fine = 2^ - 65 + 12² 21 - Î +6R.. 2. Coriolis acceleration, fermiolis ="-484 +243 +20K (Avs). tal sec. Weltal - 2x 1 J 2 -6 12 2 6 = 2 Uxw

Horizontal component of the Cossiolis force, roilastolosso Dadai sobat Horizontal & 12V w singo-x) m ame w Cost, TU EW 221 (for earth rotation) ovia suo a=300 -*7.272)2x10-5 roads. and we home, o=100m/s, ma olkg = 300.) For en zontal 2X0.1X 100 X 7.2722 X10 X Cos 30 12.695 X10-4 (And. at 24x3600 sad/s. 937 N