Question

Use the dislpacement method of analysis:

A)Calculate the bending moments in each member

b) Calculate the shear for each member

c)Draw the shear and bending diagrams

Problema 1. Use el método de Pendiente-Desviación para determinar los momentos y cortantes en extremo de barra para los segmentos AB y BC para la viga mostrada. Considere El=constante. Unidades [ kN, m] a) Calcule los momentos en extremo de barra para todos los elementos; b) Obtenga los cortantes para todos los elementos; c) Dibuje los diagramas de corte V y de momentos M para todos los elementos; Hablando: 2.5 kN / m W = a = 12.5 ; 8 m u. b= m w [kN/m] 2 B 21 1.21 a[m] b[m] + * Resuelva para la viga ABC completa; no retire la barra BC.

Answer 1

Duplacement method W=245 Kallo 42.5m fen: * T Amarang HA. TrA Tve Stepie+ Calculation of suppo realtime TO_cglewałe "suppert.reactie we willwe quilibrium equatim. ie SH=0 sign Ev=o VatVR = 2.5720.5 VA +Vg 51.25 KM O Now Now, take moment about A. : G -V8X12:5 + 215x20.5 X 10.25 =0 12.5%= 525.3125 VB = 42.025 KN VA= 9.225 KN. 2. Step 2 - Cakulation for fixed end moment forces MEAR --12:58, 12:52 MEBA = wez = +12:55KNM uj41 12 = -32.55 kNl-m 2 12 MEAL= = - -1333 Nem we2 -25282 12 12 = +13:33 KH-on, MFCB

stepsze Calculation for fixed and mimet e Mas = Menet 499 + 2510.- EES -32:55+ 450D + 2.eb110, -02:55 +0:32. EROE MBA = Mega + 2€566 +4€1.98 – 652& 32:55+ SELVA 39.737 0:64 ELOQ 12.5 MBC. MERCT YEIOS + Erge SEFE --13:33+ 4F (1.2I)0 + 2€(1:20) 0. 8 8 =-13:33. + 0.6EIQg_+0.3EIU C. Meo = M FCB + ZEIGE +4 FIDE 1333 +0.3OREL + 0.6ELO 14 • Support B_Is_poller support MAS+MBAZO - 32:55+0:12 E106 +3234 +0.64EIC =0 0.9% ELOG ETDB 20 similary Mectme - 1383 +0.6E104+05 210c +13% 3 70.3 GISHOVEL

O'qE100+ 0.963.OCCO EIDc = 0 put the waltes_in_eq, eq@,_290 cm @ get we MARE =-32:557N-m MBA = 32.55 kN-m MBC = -13.33 kNm MLB = 13:33 Kim step4- Calculation for sheer forces its take a section are between ① & 0 at distance 12 2 from £ formy SFBC = 2.572 at x=0 =0 SFC at x=8 SFR = 2011 x-x between Now take a section distance x. B & A from a pt SF ise = 2:5X8–42.025+2:5X(4-8) at x=8 SFB - 22.025N. lat x=2015 SEA 753X7SZ. 9.225KW.

Sepsit_shear_force & Bending moment dilgrams :- Æ 9.245N 20EN SED + 40 48.82 KN 22.025 RN 20 Enong -3255 RN BMD zo