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Standard Normal Distribution table for negative z Test the hypothesis using the value approach. Be sure to verify the require
sure to i Standard Normal Distribution table for positive z re OM Standard Normal Distribution .02 .03 .04 .05 .06 Z .00 .01
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Given that 200 Samble size (m) number of favorable Cases (x) = 120 Sample Proportion (@) 120 =0.60 200 = 0.60 level of signif0.1 Zo 0.03535 zo 2 . 829 is Therefore the test statistic value Zo = 2.829 P. Value The P. Value P P(z > Zo) = P(Z > 2.829) =

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