Question

Proell governor has equal arms of length 300 mm. The upper and lower ends of the arms are pivoted on the axis of the governor. The extension arms of the lower links are each 80 mm long and parallel to the axis when the radii of rotation of the balls are 150 mm and 200 mm. The mass of each ball is 10 kg and the mass of the central load is 50 kg. Determine the range of speed of the governor

Answer 1

Sol mm Given data:- Given proell governor has Ewal arms of length - 300 mm lower links radü of rotation of balle = 150 mm 4 200 mm mass of each ball cm) = 10 10 kg mass of central load CH) = 50 kg . 80 mm P P soc FC hi 300 The 80 ma 80 mat 150 200 G G B 300 1 i mg mg 2 Minimum position maximum position from the given data N, - minimum speed when radi up of yotakion Y = FG = 150 mm N₂ = matímum speed hehen radius of rolabion 92 - FG = 200 mm using pythagorovę thereom Chyp) - side +side PE .. PG". PFGFT Р 300 A PG + GF" 150

.: PG = WPF-GF C300) = 259.807 :: PG = 259.807 e 260mm height Ch, I = PG = 260 mm = 0.26 m Speedy Cminimum] CV - FM Pm+M7895 (mean hi C:FM = GD-PG = 260 mm 0.26 10+507 895 BM : BF+FM = 80+260 0.26 = 340mm = 0.34) - 15794.117 Вн NV - 0.34 10 .: N = 15794-117 is N, - 125.67 ypon Speed 3 Charinum] (N2) = FM mM 895 hz where he - PG - PF -GE 300 200 = 223.606 ..he - PG = 223.606mm 224 mm FM = GD-PG = 224 mm .:BM - BF+FM = 2247 80: 304 mm

.: NzY mrm FM Вн (mi با 895 ha 0.224 10+50 895 - [ 0304 10 Na 2 17664.473 .: Ne = 117664.473 N2 = 132.90 rpm Therefore, 9 Range of speed = N2-N = 132090 - 125.67 7.237 ypm