Question

4) A particular irreversible chemical reaction follows the rate law ratek [A] At a particular temperature the value for the rate constant is k = 3.66 x 10*5'. a) In an experiment carried out at that temperature the initial concentration of A in a system is [A]. - 7.66 x 10-2 M. What will the concentration of A be in the system att -400,8? [8 points] b) A plot of in k vs (L/T) for the rate constant for this reaction is given below. Based on this plot, find the value for the activation energy of the reaction. 8 points) 00110 0315 00120 IT

Answer 1

The answer is

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here given, rate =K[A so it it is a first order reaction, giren K = 3.66 x 10 -4 s-l we know, for Ist order reaction [^] 그. (Ao] - e-kt where, [ Ao (ra) = 7.66x10-2 t = 400 s 80 [A] - 27.66 7.66410-2 3166*10-4 4400)} Com ar [A] -6.617 7102 com) b know, for. reaction, ka A e-Ea/RT [ Eat Eu activation energy sº, enk = en A RT so enk be slope for, vs /T plot we'll R in the plot slope (-9.0 +8.0) 00 335- 0.80310) here, K (l k 0.00025 8.314 so, k. -Ea R so, Ean 5/mo 332565/8) 00025 0.00025