Question

Battery #8 is the first one (high-end rechargeable nickel metal hydride battery)

high-end rechargeable nickel metal hydride battery Use the data you collected from the video to calculate: 1. Use the voltage and capacity to calculate the battery energy in joules (J) 2. From the battery energy and mass of the battery calculate the energy density (J/g): battery energy o energy density battery mass - The calculation is explained in example 4 on the description page of this experiment 3. From the battery energy and the cost of the battery calculate the energy storage (J/$): battery energy • energy storage battery price In order to earn credit show work & briefly explain the steps of the calculation.

Battery #10 is the second one (lead acid battery)

Answer 1

Battery #8

1. The providing data in the questions are as follows-

Voltage (V) of the battery = 1.2 V

Capacity or charge capacity (Q) = (It) = 2500 mAh [Q = Ampere (I) * time (t)]

We need to find out the value of Energy (E) of a battery = ?

We remember the formula,

Energy (E) = Power (P) * time (t)

= Voltage (V) * Ampere (I) * time (t) [P = VI]

= Voltage (V) * Capacity (Q) [Q = It]

= 1.2 V * 2500 mAh

= 1.2 V * 2.500 Ah [1 Ah = 1000 mAh]

= 3 Wh [ Watt (W) = Volatage (V) * Ampere (I)]  

= 3 * (3.6*10³) Joules [1 Wh = 3.6*10³ Joules]

= 10800 Joules

So, the energy of the battery = 10800 Joules

2. Energy of the battery = 10800 Joules

Mass of a battery = 29.220 g

Applying the formula,

Energy density = (battery energy) / battery mass

= 10800 Joules / 29.220 g

= 369.61 Joules / g

3. Energy of the battery = 10800 Joules (J)

Price of a battery = 2.50 $

Applying the formula,

energy storage = (battery energy) / (battery price)

= 10800 J / 2.50 $

= 4320 J / $

Battery #10

1. The providing data in the questions are as follows-

Voltage (V) of the battery = 12 V

Capacity or charge capacity (Q) = (It) = 55 Ah [Q = Ampere (I) * time (t)]

We need to find out the value of Energy (E) of a battery = ?

We remember the formula,

Energy (E) = Power (P) * time (t)

= Voltage (V) * Ampere (I) * time (t) [P = VI]

= Voltage (V) * Capacity (Q) [Q = It]

= 12 V * 55 Ah

= 660 Wh [ Watt (W) = Volatage (V) * Ampere (I)]  

= 660 * (3.6*10³) Joules [1 Wh = 3.6*10³ Joules]

= 2376000 Joules

So, the energy of the battery = 2376000 Joules

2. Energy of the battery = 2376000 Joules

Mass of a battery = 20.203 kg

= (20.203 * 1000 g) [1kg = 1000 g]

= 20203 g

Applying the formula,

Energy density = (battery energy) / battery mass

= 2376000 Joules / 20203 g

= 117.61 Joules / g

3. Energy of the battery = 2376000 Joules (J)

Price of a battery = 140 $

Applying the formula,

energy storage = (battery energy) / (battery price)

= 2376000 J / 140 $

= 16971.43 J / $