Question

An artificial satellite is in a circular orbit ?=710.0 km above the surface of a planet of radius ?=4.45×103 km. The period of revolution of the satellite around the planet is ?=3.15 hours . What is the average density of the planet?

Answer 1

km Radius R= 4.45x10² - 4.45x10m Altitude h= 710km = 710x 10²m Period of satellite T=3.15 h = 3.15 x 60x60 s (R+h)3 GH 183 We know "T=2 TT (Rt hj} = (27) (27) 2 HE 2x3.1415 3.15x60x60 Hass of planet M= [4.45x106) + (710x103)] CM 6.67x10" - (2.05979 x 103°) (3.0699 x 15%) = 6-323x10 23 kg Volume of planet v = 2/1 R² v=1 (3.1415) (4.45X106) 8 = 3.691 X 1020m Average density of planet p = 14 = 6.323X1023 3.69141020 P=11713 kg/m² 3 3