Question

How many grams of CuCl₂ are required to prepare 1250 G of a 1.255% CuCl₂ solution,

Answer 1

$mass \, percentage = \frac{mass of solute}{mass of solution}\times100$

Given,

mass percentage = 1.255%

mass of solution = 1250gm

subsituting these values in the above equation,

$mass \, percentage = \frac{mass of solute}{mass of solution}\times100\\\\1.255 = \frac{mass of solute}{1250}\times100\\\\ mass of solute =15.6875gm$

15.6875gm is the amount of CuCL2 needed to prepare a 1.255% of 1250gm of solution.

lets see how thus make sense ,if we have a 1250gm of solution then a 10% of somwthing would amount for 125gm in thaat solution and similarly a 1% will amount for 12.5 gm in that solution . as we have to make a 1.255% our answer came out to be near to 1% that is 15.6875gm