Question

Determine the ratio of the frequency (use scientific notation and 3 significant figures) between visible lights at a wavelength of 400 nm against visible light at a wavelength of 750 nm.

Answer 1

From the concept of electromagnetic radiation, C = $\nu$ $\lambda$

c = light velocity

$\nu$ = frequency of photon

$\lambda$ = wave length of photon

For two different lights of different wave-lengths and frequencies,

$\nu$1*$\lambda$1 = $\nu$ 2*$\lambda$2

therfore, $\nu$ 1/$\nu$2 = $\lambda$ 2/$\lambda$1 = 750/400 = 1.875 = 188*10^2