Question

3. Find the equivalent resistance in the network below. .R ingingning ER R ER R R R 4. Find the equivalent resistance in the network below. 642 o na naman ar 62 3r 5.12 to ni mu odbb R = 32 24V 5. Find the currents passing through resistors R3, RS, R., and R. Ru R5 w . . 3 Ry www R2 so ga od bin Rzish Rza 85 Ry = 42 Ro Lu Rs = 62 R: = 92 Ry=7h

3 and 4) Find the equivalent resistance in the networks.

5) Find the currents passing through R2, R5, R6, and R7. See values on the left of image.

Answer 1

3 - & 3R R А 3R R ym 4 TIR 4 R 3 Last Resistances Reach senes. Their equivalent, RtR+R=3R. This 3R and R are in paralled, their equivalent RP, is B = 3 ta ..Rp, = 3R This fe, and 2 ks, are in semes. Their equivalent, Rs = Rp, +R+R=3R + 2R- Rs and R are in parallel. Their sorul, Rp2, is st TRA + ² = 1 4 2 + 1 16 senes. Hence This RP, R, and R toral equivalent, R' = Rp2tR+R = 1/R +2R = 41R 4 2006, son, see are in paralled, their equivalena, Rp RĪ * * * * * * = 1+5+10+6 Rp = in series. Their equivalent R' = Rp + 4 = 3 +4 = 4.832 5 R6 and R are in parallel. Their torud, Rp = R6 XR, ker . Rez MIR 36 30 18 15 6 Rp and 402 987 9+7 -3.9582 R6tRy semes. Their total, R = R4 + Rs tRp = 4 +6 +3.938 fui R5 Rp are in / Rs = 13.93802. Rs and are in parallel their total, Re, series. Their total, RsR₃ Rst Rg 13.93888 13.938+8 -5.082 RRY and Rp and is R=R, tR2 + Rp, = 3 +5+5.08=13.082 Total Current, I = 1.835A = 13.08 Current through Rz

B Iz 4.2 WW swing 1 Zor Iy &72 240 a-27 E I sriH F ABHIA Applying loop sude in 31+81, +5I=24 81 +8I, =24 I tI-3 1.835+1, -3 I= 3-1.835= 1.165A B Applying junction sude as I=I, + Iz a I3 = 714 1.835=1.1165+ Iz i. Iz = 0.67A = Cussent through R5 loop sule in G DEFG :. Iz 714 9 juana on sule, Iz = fg 0.67= I3 tI4 = q - 14 = 9x0.67 -0.377 A - Cusrent 16 +14 In + In thingh Ry through Iz = 7x0.377 -0.293A = current RG 9