Question

QUESTION 4 16 points Save Answer (Virtual Work Truss) Problem 4. Virtual Work Method. Determine the horizontal deflection at B. Assume all members are pin connected at their ends. AE is constant (46 points) 3 kip Bh 4 ft 3 ft B 4 ft. 6 ft. А E

Answer 1

to coor mittent rom ЗkiP no effc=0 5 4 & Fy=0 RA+RE=0 PE=3 kip ( MO AO (REX6)+ (3x8) = 0 RE - u Kip (1) RA= ukip (& ob halls 3 4 д oft Now Joint a X х {4-0 3. Floroso FCD = 3.75 kip (T) ( 3 TOLED EM=0 3= Fcosing FLD = 5kip (T) o = ton (3) -36.86989 Ev=6 FCocosot FCB = 0 FCB = ukip (o Joint B 4 FBC EV=0 FAB = FBC FAB= ukip (C) { H= 0 FBD = 0 kip FBD } FBA FDA= o Kip (zero force member sules) Joint {H=0 FAE=Okip FAB CE FAE TRA

Joint E FDE Ev=o >kip FDE sine u FDE 5kip 5 kip O=ton' (816) 0 = 53.13 & Now apply Horizontal unit loud at B D EFy=0 RAIRE = 0 EFxzo HE = 1 kip (a) MOA=0 GRE = 4 RE = 416 kip RA= 4 kip (4) 3 4 6 Fc B = Fcookip. Now as zero force member sule El=0 FBD = 1 kip (1) Joint B FBD {Vzo FBA = 0 kip ㅠ FIBA Joint A. {v=o AD COSO = 416 FAD = 0.833 Kip (T) FAD 7 FAE {H=0 4/6 FADSino + FAE=0 FAE = 0.uggg Kip (o 0=36.86989

Joint E FDE {vao FDEsino +416=0 4/6 FDE 0.833 kip (c) Member P k. L PKL AB -u 0.833 AD 0.0498 şeşm AE .u BC BD -1 çow 5 5 -0.833 DE -20.825 5 - 20.825 E PKL 20.825 N A Bh= AE AE DBH: 20.825 -) AE
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