Question

Clearly choc -D size batteries produced by MNM Corporation have had a life expectancy of 87 hours. Because of an improved production process, it is believed that there has been an increase in the life expectancy of its size batteries. A sample of 36 batteries showed an average life of 88.5 hours. Assume from past information that it is known that the standard deviation of the population is 9 hours. What is the p-value associated with the sample results? Select one O A. p-value - 0.1587 O B. p-value = 0.3413 O p-value - 0.1134 O D. p-value = 0.0921 O E None of the above answer is correct Consider the following hypothesis test: H1 H30 H1 - 20 The following results are for two independent samples taken from two populations Sample 1 Sample 2 Sample Size 35 34 Sample Mean 43 37 Sample Variance 140 170 a.) At 95% confidence, test the above hypothesis. What isare) the critical value(s) of the test statistic? Select one O A. -1.645 OB 1.669 O C..196 OD. 1.645 and 1.645

Answer 1

Solutions given data, n=36 ã = 38.5 s =9 Hai M > 87 Test statistics, 88.5-87 Z = X-4 sign 9/136 P-value = P(Z =1) =1- PlZ21) =) 1-0, 8413 = 0,1587 P-value = 0.15 87 opties Mt Ø p-value = 0,1587 Correct Given, 4,-42zo Hypothesis 4,-4270 & hq=34 n = 35 X = 43 22 = 37 82=170 s} = 140 At 95%. Confidence, Critical values = 1-C =1-0.99 = 0.05 Zoritical = 2a ==1:645 Correct option - 1-645

Given, x=0.05 Neell Hypothesis is Rejecked. Hoi Average length of stay in RPH is equal to average bergen of stay in Gh. HA : Average length of stay in RF H is significantly less than the average length of stay in GH. Ho - Rejected Conclusions comment option MA © conclude the length of stay in RFH is significantly less than qu, at two local malls Independent random sample taken Null & Alternative hypothesisy optian Hy A Ho: M, - M2=0 Hai 4, -M2 70 Comeet (5) Given data, n=go C=95% =0.95 (confidence) X=1-C=0.05 One-tailed test ( Upper teiled] Zontical 20 1,645 comect option is (В Greater than 1.645