Question

Q.1 Work out the No. of bags of cement required for the plastering of a two-room building, having internal dimensions of rooms as 13 x 11' x 12 each. All walls are 9 in. thick. There are three doors (4 x 7'each). Two windows (5 x 5 each), Four ventilators (2.5 x 1.5/cach), in the room. Take P.L. = 2.5/ Thickness of plaster as in. Parapet wall = 2.0/ high above roof detail. (Assume other specifications yourself).

Answer 1

12.5 13 plan : 12' பள்ளி 6 Plinth level 2.5 Xound level 94-5 Final calculation : 1:3 ratio Take as 69.96875 eft Mortar 69.96875 X 1.6 coment (: 60% increase void ratio (1+ 3) remarks. 27.9875 Ft 1. 226 cft 1 Cement bag x 27.9875 - 22.828 27.9875 Ft 1.226 ~ 23 bags

5.no Description 1 upto Plinth level quantity (nos.) Lift) 1 H(ft) Area (sq. ft) Remarks 135 2*(14.512.5)-L; outer distance = inner dist+2* wall thickness 54 2.5 1 48 54 12 12 2 walls upto roof level inner wall outer wall Deduction windows ventilators 576 648 outer length = inner length + 2 wall thickness 1 21 5 5 2.51 -50 openings have to be deducted twice, due to wastage deducted once - 15 openings have to be deducted twice, due to wastage deducted once 4 1.5 3 ceiling 1 13 11 143 1 2 4 Parapet wall finner side outer top surface 48 54 2 96 108 38.25 total area - inner area = 12.5 14.5 - 1311 1 total 1679.25 sq.ft volume area * thickness: 1679.25*0.542 69.96875