Question

need help!

ns 0.7 0.3 or For the transition matrix P= solve the equation SP ES to find the stationary matrix S and the limiting matrix P. 0.3 0.7 tre mal S=0 (Type an integer or decimal for each matrix element. Round to the nearest thousandth as needed.) ons P=0 (Type an integer or decimal for each matrix element. Round to the nearest thousandth as needed.) sition the li Tra Appli n ma lo For atrix S ordan Enter your answer in each of the answer boxes y matrix = found by solving the equation - SPS include SPS 12 7/3 e

Answer 1

Ang. 10.7 0.3 Transition matrix, p = 0.3 07 Setup a Markov let Chain with two States si and S2 let Sa [sı sa ] Condition SP=S [s. S2 Fo7 03 [si Sz] 07 w 0.75,+ 0.3 S2 = 5 0.3 sito 7S2 = S2 V -0-35 +0.352 =o 11 0.35i 0:3S2 0 Now due to markov Chain Sit S2 = 1 3 Si=(1-S2) put si in

☺ -0-3 (1-52] + 0.3 S2 = 0 -0.3 +0.352 +0.352 O 0.652 = 0.3 S2 = 03 = /2 06 S2 = 0.5 Si=1-S2 Si= 1-os Si=o.s so Stationar matrix would be s S = [s, S2] = [0.5 0.5] ANS each sow canal to B) limiting matrix ł has Stationary matrix S. Thus, SI S2 cos 0.5 11 S2 OS o's Ans.