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с 36° b=7 A a = 14 Solve the triangle. Round the lengths of sides to the nearest tenth and angles to the nearest degree. B o
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Answer #1

Ico let a=14 A с B :.Le = 180°-160-360 128° a=14, le-it ces C - e24a²-a Rb a cosine rule) 49 +196-e2 28-3- Cos(128) = (27+ (1

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