Question

There is a string L= 11 cm fixed at a turn while a 4-kg molecule swinging from it. The framework experiences simple harmonic motion. At t = 0 the molecule is situated at a point θ = 13° relative the harmony and has zero speed, so the movement of the molecule is depicted as θ(t)=θmax⋅cos(ωt).

g L m 1

What is the frequency and period?

f = Unit in Hz

t = Unit in s

Discover the amplitude, maximum angular acceleration, and maximum angular speed.

θ_max = Unit in rad

Ω_max = Unit in rad/s

α_max = Unit in rad/s²

Look for the molecule's angular position at t = 4.01 s

θ = Unit in rad

Answer 1

L = 11cm 11x102 T= time period - 2K ſ 3 9,8 0.66 sec f = = 0.66 1.51HZ. 13 *t radian = 0.23 rad. QTf 2x3.141X1,51€ 9,48 ford's = 0.23x(9,48² May = 20.68 rad/5² O max 130 180 Imax amat o mat 122 0 = 0.23 los (9.48X 4.01) = 0.23 los (38.01) 0.23 x 0.94 - 01216 rad'