Question

TUELLTYESU part only changes if you submit Assignment Scoring Your last submission is used for your score. 1. (-/3 Points] DETAILS OSCOLPHYS2016 16.1.P.001 M Fish are hung on a spring scale to determine their mass (most fishermen feel no obligation to report the mass truthfully). (a) What is the force constant (in N/m) of the spring in such a scale if it stretches 7.80 cm for a 13.0 kg load? N/m (b) What is the mass (in kg) of a fish that stretches the spring 5.50 cm? kg (c) How far apart (in mm) are the half-kilogram marks on the scale? mm

Answer 1

For a load hanging on a spring , the force will be , F = Kx

Again , F = mg , weight of the load.

So , kx=mg=> k=mg/x

Gliver mass of the woad, maiso Displacement, nr 7.80 cm a 0.0980 m. According to Hoona's ow, the force one to the wad Fokni constant, Again, weight of the wad fringaw momg' > i ka force g Ka 13 kg x 9.8 mis a 1633 N/m. 0.0780 m (a force wrstart, Ka 1633 W/m min, км > g kn ang a The fish stretches the spring, n o 5.50 cm a 0.0550 m 1633/m x 0.0550 m 9,8 m & 9.2 kg now ☺ mass of the fish ma 9.2 kg) ng 0.5 kg on sugx, sms = 3x10 & Half Kilogram marks wil ne 3 mm & lag 163B dlm ma 3 mm. apart.