Question

Can you help me to solve this question, please:)

B1. (a) A DC circuit is shown in Figure Bl. 1092 B A 802 702 1402 18V Figure B1 Calculate (i) the total resistance across A and B (RT); (5 marks) (11) the total current from the DC supply (Is); (3 marks) (111) the potential difference(p.d.) across the 1422 resistor (V149); (2 marks) (iv) the current flowing through 1022 (11092); (3 marks) (v) the power dissipated by RI (PT) (2 marks)

Answer 1

Simply apply the basic electrical circuit laws and calculate the values.
all Chuen circuit A 1401 18V 15 n resistor will be in parallel to lon B 8r 7 la Let total resistance across A & B be Li Now, here, fr & or resistors are in series they will added and a resistor of 7+8= 15r Now this give resistor of a will they رمله lor OXIS бл 10+15 Finally, مه this 6r resistor comes comes in series with 14N will be added and they given total resistance across A & asi 20 r Aus Ri= 14+6 current de from lb Now, for Jotal supply total resistance circuit with the drawn (Ra) the and supply as; voltage

Rr=zon Soi As, v=IR Is 18 = Isx20 = 0.9 Isa 18 18V 20 Is 0.9A Aus 14n resistor can across © The potential difference be given as 141 6л. since combination of Is lor, 71& or resis for comes as on 2 {n } 18V ce do, here, Is = 0.9A will be, And potential drop across 14 Viura Is x 14 - 0.9 x14 Vi= 12.6. V Aus we ( d , Now, for current & draw the current through lon resistor circuit given will apply division rule, the current

I, (ол 144 Iz isr Is С" H 18V. Let I be the current flowing through 10n resistor, formula, Soi werent division by Current diuision Rule I I2 I = Is x 15 10+15 R. 3R₂B so I = 0.9x15 I = I x R2 RITR2 25 I, 0.54 Aus & Iz= IXRI RitR2 across RT Now, for power dissipated that power across resistor can be kle know, . هره given p=1²R can be given as for RTI power dissipated can P= I RJ Is O.GA Rr=2on 0.9)ex22 = 16.2 la : 2019 P Aus