In regards to binary search tree, can you answer why a BST with N nodes has...
In regards to binary search tree, can you answer why a BST with N nodes has at least log2N levels and at most N levels. so the runtime complexity is best case 0(logN) and worst case 0(N). Can you explain this with the following numbers in this order? 7,1,64,28,77
Homework Answers
There are two cases for a BST, balanced BST and unbalanced BST. Unbalanced BST is a skewed BST. For a balanced BST, for every node, the difference between the left height and right height is atmost 1.
For a balanced BST, there will be logN levels and for an unbalanced tree, there will be N levels. Time complexity is O(height) where height is the height of the tree. For a balanced BST, height is logN and for an unbalanced BST, height is N, hence the time complexity.
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In regards to binary search tree, can you answer why a BST with
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