Question

QUESTION 6: 15 marks 15 points A pulse tracer experiment was conducted in a tubular reactor and RTD function E(t) was calculated and tabulated belowin Table 1. An irreversible, aqueous-phase, elementary reaction, 2AB+C, with k = 0.5 L.mol-1 min -1 at 320K will be carried out isothermally at 320K in this reactor, whose mean residence time was found to be 15 min from RTD studies. The feed concentration of A is 2mol/dm3. Determine the conversion that can be attained in this reactor for the following 2 cases: a) Assuming that the reactor were an ideal PFR. (4 marks) b) Using the complete segregation model for its non-ideality. Compare and comment. (11 marks) t, min E 0 0 5 0.03 10 0.05 15 0.05 20 0.04 25 0.02 30 0.01 35 0 Table 1: RTD data 1 Add File

Answer 1

Sicked bud Tecla 2A-B+C kas Hastning T3zok 1min ne2 chos a malam Now According to the Pung frow Reactor Equation صلالی din htto ruit n-2 KEA Vocno dia XX Cho [H0]? dia •5x2[-nAT² du. 15 VA (1-818 (1-mal? 15 15 -Ир. (x-1 16 - I-1 x-1 І: Иn Samal

Data ISH 1 1- L 16 I-1 16 Иа 16-1 16 15 16 this is ideal PER Now Now •9375 = 15 16 93175% Az Now for Non idsality Now lo 20 5 104 +02 03 05 E te 175 6. y 7 2 Now find out total & from a to 25 tedt Stade Now By trup azoidal formule Wy) (19=136) 42 (4-3-3 5 [10 +014 ( 15418-6:35 +od+staly

Dar (1x1x5 sar 3 35 ² 2 25735 2 Stadt 15/05 0 24481 min Es Qura min Now for ideal Reacted din na -doo kt lonlcht CA CAO CA C692 1 1 Now for I =15 1 - Ktt Cooktel CAO Shanthi LA Edt peaton Cho SA

Date Edt hopott I EDA 5221 S [ Edd Che maup.024489 In [xx] 10249 89 In [5+1] - Ingo] 2.7725 X:02yYgg = .0 67897, TA 067897 X 2 1357958 Now 25921 • 1357958 -9321 (Ao-( JIA 92305 In - 93.21% For Non ideallity SA