Question

Three identical metallic spherical objects have individual charges of, q, = -8.01 nC, q2 = +1.602 nC and q3 = +8.01 nC. If the three objects are broght into contact with each other at the same time and the separated, determine: a) the final net charge on G1 = nC; b) the final net charge on Q2 = nc c) the final net charge on 4 - d) the number of electrons that were removed from/added to Q1 = electrons were nC; 91.

Answer 1

on - o - = = q 3 = / Initial charge sphere 2, -8.0l nc Initial charge sphere 2 22 t1.602 nc Initial charge m sphere 3 + 8.ol nc since metallic spheres identical , so their radius will be Let rading of each spherical object =r Potential of q, three spheres is same 2 3 are Samme 2 221 23 U Initial Charges on Let Final 2; ; 2² and 23 Intermediate three spheres are spheres 1, 2 and 3 respectively, on O q () (separated) q, 23 Final Now, Total on - 2 = Initial charge system of spheres is q 2, +92 +23 =) q - 8.0inc t1-602 nc+8.0inc =) q = 1.602 nc 0 Now, Total Final charge on system of spheres is 2' + So, By Lenservation of charge hare Total initial charge on = Total final Charge system = q 1.602 nc ai + 2 + 2's 3 q; +42 +q's 1.602 nc qf 2ź + 9,3 2 system qf 교 교

។ is S كم Now, potential (electric potential ) potential ) of sphere 1 is 2', Vi Y a Er Electric potential of sphere 2 qa u Ror Electric potential of sphere 3 is 912 V ЧТ£, % Now, When three objects Contact they have potential V = V2 = V? So, using and 6 in we get 23 3 6 = are same so hare / / 17 J 5 / ) qi 3 r 470 Чле, а y ñ or 8 q 3 me / - 8 we So, from / al =q's Using in get qit qit qi 1-602 nc 321 = 1.602 nc qi =0.5 34 nc hare, q;= 42 = 23 = 0.534 nc (a) The final net charge on q, = 2;' = =0.53unc (b) The final net charge on 22 22 =0.53ync (C) The final net charge on qz = 0.534 nc (d) Initial charge on q, is negative and final charge on q, is positive. to attain positive charge electrons must be remored from sphere lo So, positive Charge = q3 Sol . transfered to to sphere I is

(3 q =) m q=2,'- 2 -) = 0.534 nc - (-8.01nc) q 0-5 34 nc + 8.0l nc =) q=8.544 nc -19 of charge Magnitude electron =e 1.6 x 10 19 Let number of electrons removed from sphere in Then by quantization of charge have 오 Inc=109c q = ne - 9 8.54 unc 8.544 X10 h = n = į.6 xlo -19 me 0 0 n= С 刀 L-6XLO -19 ( -) n = 5.34 X1010 from q, is So, number of electrons remored 5.34 Xlo jo