Question

A Imagine a negatively charged particle, A approaching another negatively charged particle, B, along the path shown in the diagram. A moves from point X to point Y. These two particles form an isolated system, which means no work is done by external forces; therefore, the system's total energy does not change. A foelsan clectrical force (an repelling force) from B while it approaches B. Therefore, work is done on B, but the effect of this work is to transform potential energy in to kinetic energy for vice versa); it has no effect on the system's total energy Bis much more massive than A (more inertia than A), so it accelerates much less than A. Therefore, we can say that has essentially zero acceleration, and therefore, constant velocity. We can watch this system from a reference frame in which that constant velocity is rero. Imagine that you are sitting on B. It will seem to you as if you and are sitting still and A is orbiting around you.) Aqio 1. B creates electric field at all points in the space around it. If we drew electric field lines to represent this field they would be straight lines that point away from B, curved lines that flow away from B straight lines that point toward B, curved lines that flow toward BI. 2. Balso creates electric potential at all points in the space around it. This potential is positive at all points, negative at all points, positive at some points and negative at other points 3. As A gets closer to B. A sees the electric potential increasing, decreasing. maintaining a constant value] 4. When A comes close enough to interact with B, the system now has electric potential energy. This potential energy is positive no matter where Als negative no matter where Als, posltive for some locations of a and negative for other locations of AJ. 5. As A gets closer to B, the system's potential energy increases, decreases, maintains a constant value] 6. Therefore, the system's kinetic energy increases, decreases, maintains a constant value 7. This is consistent with what we already know about forces and accelerations. At point A particle A's velocity is pointing approximately straight at particle B. At that moment, the force from Bon A points in the same direction as the direction opposite to A's velocity 8. Therefore, A's acceleration points in the same direction as A's velocity the direction opposite to A's velocity no direction, since acceleration is zero 9. Given those directions for force and acceleration that you figured out in parts 7 and you know that at this moment, A must be speeding up, slowing down, maintaining a constant velocity and that means the kinetic energy must be increasing, decreasing, maintaining a constant value)

this is one question with many parts, thanks for the help!

Answer 1

Som 011) Straight lines that point towards B as lines Starts boom Dive Charge and end.com (В. Give Charge 5 (2) Electric potential is negative at all points at external energy redurred to move from one position to another (3) Electric potential a So it, bis decreasing they the electric potential f increases () dese alonge dy said potential Saefective no matter U= -K9 Increases as the r is decreasing (6) Since potential is increasing so the Kinetic ene decreasy enerzy (7) Here the force of A. Teplus.com is opposite to the As velocity (8) As the A approaching to B is kinetic energ its velocity that is retos dentron Us onec cousing able the release hom (Tetorsleton) is opposite to (a) As the kinetic energy A is slowing down В, decreases le de creating hand, the
plz do like i Badly need it