Question

Show IntrodInstructions Out of 100 people sampled, 35 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to four places <p Get Help Points possible: 1 This is attempt 1 of 2 Sub

Answer 1

$x=35,n=100$

$p=\frac{x}{n}=\frac{35}{100}=0.35$

$q=1-p=0.65$

pg 0.35 x 0.65 100 0.002275 = 0.048 n

Za P9 = 1.96 x 0.048 = 0.0935 n

Confidence interval is

$p-Z_{\frac{\alpha }{2}}\sqrt{\frac{pq}{n}}< p< p+Z_{\frac{\alpha }{2}}\sqrt{\frac{pq}{n}}$

$\Rightarrow 0.35-0.0935< p< 0.35+0.0935$

$\Rightarrow 0.2565< p< 0.4435$