Question

Part A A solenoidal coil with 25 turns of wire is wound tightly around another coil with 350 turns. The inner solenoid is 22.0 cm long and has a diameter of 2.40 cm. At a certain time, the current in the inner solenoid is 0.110 A and is increasing at a rate of 1700 A/s. For this time, calculate the average magnetic flux through each turn of the inner solenoid. Express your answer in webers. Ivo A20 ? Wb Submit Request Answer Part B For this time, calculate the mutual inductance of the two solenoids. Express your answer in henries. VALD ? M= H Submit Request Answer Part C For this time, calculate the emf induced in the outer solenoid by the changing current in the inner solenoid. Express your answer in volts. EVO AXO ?

Answer 1

h = 25 turns 350 turry in. 22cm = 0.22 m 0.024 m 2-40 cm I in Elt 0110 1700 Als & 0 2 I Mo Ng I 2 BA - ) , R o (417x10?)(350) 0.110) (0.22 ) ***{F) (04)] 8 a g. 95 X lo Wh 62 mi = m₂ =m (25) (9.95x108) 1 0.110 ma 2:26 X 10 Н. lei E. 1 di -2.26X1005) (1700) 2 -3.84 x 10 0.0 384