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The average final exam score for the statistics course is 77%. A professor wants to see if the average final exam score for s
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Answer #1

x

x2

79

6241

65

4225

57

3249

72

5184

84

7056

54

2916

60

3600

69

4761

69

4761

85

7225

58

3364

79

6241

Total

831

58823

n=12

Sample mean 831 * n 12

x = 69.25

The standard deviation of sample is given by

Σχ2 (Σα)? In s = η -1

58823 (831) 712 S = 12 - 1

58823 – 57546.75 S= 11

s= V116.0227

s = 10.7714

Answer(a):

For this study, we should use one sample t-test

Answer(b):

H0: _u = 77

H1: μ<77

Answer(c):

The test statistic to test the above hypotheses is

t = x-t SW Vn

69.25 – 77 t 10.7714,12

-7.75 t = 3.11

t = -2.492

The value of test statistic for above test is -2.492

Answer(d):

The p-value for above test is 0.015

Answer(e):

We have level of significance, α=0.05

The p-value is Less than α

Answer(f):

Based on this, we should Reject the null hypothesis.

Answer(g):

The correct option is C.

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