Question

1. A single slit forms a diffraction pattern, with the second minimum at an angle of 40.0° from central maximum, when monochromatic light of wavelength 630 nm is used. What is the width of the single slit?

2. Consider a two-slit experiment in which the slit separation is 3.0 × 10^-5 m and the interference pattern is observed on a screen that is 2.00 m away from the slits. The wavelength of light passing through the slits is 420 nm. What is the position of the second dark fringe?

3. Find the position of the first dark fringe in nm knowing that the green light has a wavelength of 500 nm, the one slit at a distance of 1150 nm from the screen, and the slit width 850 nm.

4. Using the same settings as for the question above, find the width of the central bright fringe.

Pleas show all work and explain

Answer 1

For single sit let diffraction pattern. midth=a Sino Sinuo 2x630x lo = 2x a = 1.96x lo 2. slit separation 2 = 3x15 m Screen distance D = 2 m = 42oxiom Porzend for second dank fringe Sino = 2x 2d also for small o sino 7 lono = Š Y=2x420x10 3x105 y = 280x10m D = 1150x10 m a = 850x10m ,a=500x10 m Single slit diffracion sino my also sino a tone = f = ml - 4 = 115ox 10 x 1x500x10 850 x 109 Y = 676.47 nm " width of central maxima 2y = 2 x 676.47 ok 22 3 - 1352.94 om