Question

21. [2] Look at Figure 30-26 and you will see a capacitor charge and discharge curve in B. for the circuit shown in A. Will the capacitor charge faster, slower or take the same time if the battery voltage in Figure 30-26A is changed from 10 volts to 20 volts and why?

Answer 1

a) $4 MA R=0.5 m2 Vs Ş: 2 с U C-10 pF Vet Vs2100 volt a in the given question, Capacitor circuit in demonstrated. The circuit consists of Resistor R, a voltage source Vs & two switches & S. for for the switch si i connection, the capacitor is charged. Au scobis charges CS R with Se connected, through si CamScanner

The charging & dis charging graph of capacitor ic is like, loot. Charging Ve 563.2 V 3618 v Discharging T 2T 3T we can see tere So from the graph charging and discharging curve of c. Now from the circuit ofter one time constant (T) the capacitor 6312 Volt & dis Charges to es changed with to Bongcarner

Now from the circuit, Vse Rit į Sidt If is current through circuit, So, boy By Laplace transform, (Rt és ) Ils), Ils).. CVS It RCS L & Ns Now vel), és 163) IARCS - sala S It RCS let Rca T (time constant) i', V(6) 22. Vs RC s st the So vilt) 2 Vs Rc 0 LE RC 2 Compiment *RC [-et/RC] V (H) = us [irë ta 12 Vs t Re CS Scanned with CamScanner

So Capacitor Noltase for the charging a Velt). Now if the supply voltage Vs 100 volt. then after. I timme constant vaja vsa Cine''), 2 : 100 x 0,632 = 63.2 volt Now In the question, it is given that the supply voltage is changed from to for that What will be the charging rate of to 20 volt, Case capreitor. DIY Vs 10N, If then, after 1 time constant, to T vero) a 10x (-e-17) = 10 x 0-9 Ć 6:32 2 63.2% of Vs volti CS Scanned with CamScanner

as Now If us change from 10 to 20 volt, Hur other circuit parameter (R&C) are san So. capacitor voltage after 1 Time Constant will be ve (T) Cine) 12.64 volt 26312% of vs So, At both case rate of Charging dva usad (-ė e-t/7) 20x at at 2 Ws -t/T e & dve avi 2 vse osta Cleet o) - d vs ett T So. At both case the rate of charging will be Same i As the time constant of the circuit haal is same. At both case, after after one tince constant (T) the capacitor voltage will be VT) = 63.2% of Vsi for both case the capacitor will cohas take same time to reach 63:2% of the supply odotegevith CS CamScanner