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mi m2 Consider the following: MA - 3.6 kg my - 5,4 kg What is the TENSION in the string connecting the blocks? Consider the p

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Answer #1

For A

  T-m_Ag = m_Aa

for B

m_Bg-T = m_Ba

solving the above two equations

tension \ T = \frac{2m_Am_Bg}{m_A+m_B}

  tension \ T = \frac{2\times3.6\times5.4\times 9.8}{3.6+5.4} =42.3 \ N

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