Question

What is the output of the following c program. Why, Can you tell me how do you solve it?

#include <stdio.h> int fun(int n) { if(n==0) { return 1; } else return 7 + fun(n-2); } int main() { printf("%d", fun (4)); return 0; | }

Answer 1

THE GIVEN SOURCE CODE IS:

#include<stdio.h>
int fun(int n)
{
if(n==0) {
return 1;
}
else
return 7 + fun(n-2);
}
int main(){
printf("%d",fun(4));
return 0;
}

THE OUTPUT OF THE ABOVE PROGRAM WILL BE: 15

THE SCREENSHOT OF THE OUTPUT IS BELOW:

(base) mouli Lenovo-G580:$ gcc sc.C (base) mouli@Lenovo-G580:~$ ./a.out 15(base) mouli Lenovo-G580:~$

DETAILED EXPLANATION:

IN THE main() WE CALL fun(4).

THEN IT WILL SEARCH FOR fun() OUTSIDE A main().

IF fun() FOUND THEN IT WILL EXECUTE ALL THE INTRUCTIONS INSIDE IT.

cases:

fun(4):

here n!=0 so the return value is 7+fun(4-2) //output=7

fun(2):

here n!=0 so the return value is 7+fun(2-2) //output=7+7

fun(0):

here n=0 so return value is 1 //output=7+7+1=15.

I HOPE THIS WILL HELP YOU.........